Problem :

You are given N integers.Sort the N integers and print the sorted order.
Store the N integers in a vector.Vectors are sequence containers representing arrays that can change in size.

Declaration :

vector<int>v; (creates an empty vector of integers)

Size :

int size=v.size();

Pushing an integer into a vector :

v.push_back(x);(where x is an integer.The size increases by 1 after this.)

Popping the last element from the vector :

v.pop_back(); (After this the size decreases by 1)

Sorting a vector :

sort(v.begin(),v.end()); (Will sort all the elements in the vector)

To know more about vectors, Click Here

Input Format :

The first line of the input contains N where N is the number of integers. The next line contains N integers.

Constraints :

• 1 <= N <= 105
• 1 <= Vi <= 109 , where Vi is the ith integer in the vector.

Output Format :

Print the integers in the sorted order one by one in a single line followed by a space.

Sample Input :

5
1 6 10 8 4

Sample Output :

1 4 6 8 10

Solution :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int n;
    cin >> n;
    vector<int> v;
    int a;

    for (int i = 0; i < n; i++) {
        cin >> a;
        v.push_back(a);
    }
    sort(v.begin(), v.end());
    for (int i = 0; i < n; i++) {
        cout << v[i] << " ";
    }
    return 0;
}

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