# Vector-Sort – HackerRank Solution ## Problem :

You are given `N` integers.Sort the `N` integers and print the sorted order.
Store the `N` integers in a vector.Vectors are sequence containers representing arrays that can change in size.

Declaration :

``vector<int>v; (creates an empty vector of integers)``

Size :

``int size=v.size();``

Pushing an integer into a vector :

``v.push_back(x);(where x is an integer.The size increases by 1 after this.)``

Popping the last element from the vector :

``v.pop_back(); (After this the size decreases by 1)``

Sorting a vector :

``sort(v.begin(),v.end()); (Will sort all the elements in the vector)``

### Input Format :

The first line of the input contains `N` where `N` is the number of integers. The next line contains `N` integers.

### Constraints :

• `1 <= N <= 105`
• `1 <= Vi <= 109` , where `Vi` is the `ith` integer in the vector.

### Output Format :

Print the integers in the sorted order one by one in a single line followed by a space.

### Sample Input :

``````5
1 6 10 8 4``````

### Sample Output :

``1 4 6 8 10``

## Solution :

``````#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
int n;
cin >> n;
vector<int> v;
int a;

for (int i = 0; i < n; i++) {
cin >> a;
v.push_back(a);
}
sort(v.begin(), v.end());
for (int i = 0; i < n; i++) {
cout << v[i] << " ";
}
return 0;
}``````

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