Problem :
In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia
Task :
Given an integer, n
, perform the following conditional actions:
- If
n
is odd, printWeird
- If
n
is even and in the inclusive range of2
to5
, printNot Weird
- If
n
is even and in the inclusive range of6
to20
, printWeird
- If
n
is even and greater than20
, printNot Weird
Complete the stub code provided in your editor to print whether or not n
is weird.
Input Format :
A single line containing a positive integer, n
.
Constraints
1 <= n <= 100
Output Format :
Print Weird
if the number is weird; otherwise, print Not Weird
.
Sample Input 0 :
3
Sample Output 0 :
Weird
Sample Input 1 :
24
Sample Output 1 :
Not Weird
Explanation :
Sample Case 0: n = 3
n
is odd and odd numbers are weird, so we print Weird
.
Sample Case 1: n = 24
n > 20
and n
is even, so it isn’t weird. Thus, we print Not Weird
.
Solution :
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
String ans="";
if(n>=1 && n<=100){
if(n%2==1){
ans = "Weird";
}
else{
if(n>=2 && n<=5 ){
ans= "Not Weird";
}
else if (n>=6 && n<=20){
ans = "Weird";
}
else if(n>20) {
ans = "Not Weird";
}
}
}
else{
ans="Invalid no! Enter a number between 1 and 100.";
}
System.out.println(ans);
}
}
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