# Java If-Else – HackerRank Solution ## Problem :

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Given an integer, `n`, perform the following conditional actions:

• If `n` is odd, print `Weird`
• If `n` is even and in the inclusive range of `2` to `5`, print `Not Weird`
• If `n` is even and in the inclusive range of `6` to `20`, print `Weird`
• If `n` is even and greater than `20`, print `Not Weird`

Complete the stub code provided in your editor to print whether or not `n` is weird.

### Input Format :

A single line containing a positive integer, `n`.

Constraints

• `1 <= n <= 100`

### Output Format :

Print `Weird` if the number is weird; otherwise, print `Not Weird`.

### Sample Input 0 :

``3``

### Sample Output 0 :

``````Weird
``````

### Sample Input 1 :

``24``

### Sample Output 1 :

``````Not Weird
``````

### Explanation :

Sample Case 0:  `n = 3`

`n` is odd and odd numbers are weird, so we print `Weird`.

Sample Case 1: `n = 24`

`n > 20` and `n` is even, so it isn’t weird. Thus, we print `Not Weird`.

## Solution :

``````import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
String ans="";

if(n>=1 && n<=100){
if(n%2==1){
ans = "Weird";
}
else{
if(n>=2 && n<=5 ){
ans= "Not Weird";
}
else if (n>=6 && n<=20){
ans = "Weird";
}
else if(n>20) {
ans = "Not Weird";
}
}
}
else{
ans="Invalid no! Enter a number between 1 and 100.";
}

System.out.println(ans);

}
}``````

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