For Loop – HackerRank Solution

For Loop – HackerRank Solution

Problem :

for loop is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>
  • expression_1 is used for initializing variables which are generally used for controlling terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Input Format :

You will be given two positive integers, a and b (a <= b), separated by a newline.

Output Format :

For each integer n in the interval [a,b] :

  • If 1 <= n <= 9, then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
  • Else if n > 9 and it is an even number, then print “even”.
  • Else if n > 9 and it is an odd number, then print “odd”.

Note :

Sample Input :

8
11

Sample Output :

eight
nine
even
odd

Solution :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

    int a, b;
    string represent[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    cin >> a >> b;
    for(int i = a; i <= b; i++) {
        
        if(i > 9) {
            if(i % 2 == 0)
                cout << "even\n";
            else cout << "odd\n";
        }
        else {
            cout << represent[i]<<endl;
        }
    }
    return 0;
}

 552 total views,  2 views today

Leave a Reply

Your email address will not be published. Required fields are marked *