# For Loop – HackerRank Solution ## Problem :

for loop is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

``````for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>``````
• expression_1 is used for initializing variables which are generally used for controlling terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.

A sample loop will be

``````for(int i = 0; i < 10; i++) {
...
}``````

Input Format :

You will be given two positive integers, `a` and `b` (`a <= b`), separated by a newline.

Output Format :

For each integer `n` in the interval `[a,b]` :

• If `1 <= n <= 9`, then print the English representation of it in lowercase. That is “one” for `1`, “two” for `2`, and so on.
• Else if `n > 9` and it is an even number, then print “even”.
• Else if `n > 9` and it is an odd number, then print “odd”.

Note :

Sample Input :

``````8
11``````

Sample Output :

``````eight
nine
even
odd``````

## Solution :

``````#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

int a, b;
string represent = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
cin >> a >> b;
for(int i = a; i <= b; i++) {

if(i > 9) {
if(i % 2 == 0)
cout << "even\n";
else cout << "odd\n";
}
else {
cout << represent[i]<<endl;
}
}
return 0;
}``````

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