Problem :
You are given an integer n
. Check if n
has an odd divisor, greater than one (does there exist such a number x
(x>1
) that n
is divisible by x
and x
is odd).
For example, if n=6
, then there is x=3
. If n=4,
then such a number does not exist.
Input :
The first line contains one integer t (1≤t≤104)
— the number of test cases. Then t
test cases follow.
Each test case contains one integer n (2≤n≤1014)
.
Please note, that the input for some test cases won’t fit into 32
-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output :
For each test case, output on a separate line:
"YES
” ifn
has an odd divisor, greater than one;"NO"
otherwise.
Sample Input :
6
2
3
4
5
998244353
1099511627776
Sample Output :
NO
YES
NO
YES
YES
NO
Solution :
// <-Coded by Pasindu Piumal->
#include <bits/stdc++.h>
using namespace std;
#define ll unsigned long long int
#define ld long double
#define str string
#define F first
#define S second
#define pb push_back
#define mp make_pair
int mxN=1e5;
ll n;
void solve() {
cin >> n;
while(n%2==0)n/=2;
if(n==1)cout << "NO\n";
else cout << "YES\n";
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while(t--) {
solve();
}
return 0;
}
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