Polycarp remembered the 2020-th year, and he is happy with the arrival of the new 2021-th year. To remember such a wonderful moment, Polycarp wants to represent the number n as the sum of a certain number of 2020 and a certain number of 2021.

For example, if:

- n=4041, then the number n can be represented as the sum 2020+2021;
- n=4042, then the number n can be represented as the sum 2021+2021;
- n=8081, then the number n can be represented as the sum 2020+2020+2020+2021;
- n=8079, then the number n cannot be represented as the sum of the numbers 2020 and 2021.

Help Polycarp to find out whether the number n can be represented as the sum of a certain number of numbers 2020 and a certain number of numbers 2021.

### Input :

The first line contains one integer t (1≤t≤104) — the number of test cases. Then t test cases follow.

Each test case contains one integer n (1≤n≤106) — the number that Polycarp wants to represent as the sum of the numbers 2020 and 2021.

### Output :

For each test case, output on a separate line:

- “YES” if the number n is representable as the sum of a certain number of 2020 and a certain number of 2021;
- “NO” otherwise.

### Input :

```
5
1
4041
4042
8081
8079
```

### Output :

```
NO
YES
YES
YES
NO
```

## Solution :

```
// <-Coded by Pasindu Piumal->
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define ld long double
#define str string
#define F first
#define S second
#define pb push_back
#define mp make_pair
int mxN=1e5;
ll n;
void solve() {
cin >> n;
int p=n%2020, k=n/2020;
if(p<=k)cout << "YES\n";
else cout << "NO\n";
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while(t--) {
solve();
}
return 0;
}
```

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